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Divisibility Rules Practice Questions with Detailed Solutions – Level 3

Hard divisibility problems on missing digits for composite divisors, remainders using pair-sum and triplet methods, and numbers built from repeated digits or blocks.

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Questions, answer key and solutions.

Questions
50
Duration
75 min
Marks
50

Negative marking

Attempts
100
Access
Free

Normal practice, or a Simulated test

Both use the same questions. Normal practice is untimed and needs no account: choose an option and the answer and solution appear at once. The Simulated test is the real computer-based format, with one 75-minute clock, a question palette and full screen, and your score, the key and the solutions arrive when you submit.

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Simulated

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The computer-based test format: one clock, a question palette, and a score the moment you submit.

  • A clock that does not pause. 75 minutes from the moment you begin, and the paper is submitted for you when it reaches zero.
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  • Full screen, proctored. The test takes over the screen; leaving it three times submits the paper.
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About this test

Divisibility Rules Level 3 Practice Quiz: Missing Digits and Remainders

Aptitude360's Divisibility Rules Level 3 set is for quantitative aptitude learners who already know the basic tests and want hard Number System practice. It covers missing-digit problems for composite divisors, remainders by alternating and grouped-digit methods, and numbers made by repeating a digit or block. Every question comes with a worked solution.

Topics covered in this hard divisibility set

  • finding missing digits when a number must be divisible by a composite divisor
  • counting digit pairs that satisfy a divisibility condition
  • remainders using the alternating digit sum, the pair-sum method and the triplet method
  • numbers formed by repeating a single digit or a block of digits, including repunits
  • palindromes and numbers made by repeating a three-digit block
  • least number to add or subtract for divisibility by several divisors at once

Key divisibility rules and formulas

  • Alternating-sum rule for eleven: \( N \equiv a_{0}-a_{1}+a_{2}-a_{3}+\cdots \pmod{11} \)
  • Pair-sum rule for ninety-nine: \( 100 \equiv 1 \pmod{99} \)
  • Triplet rule for thirty-seven: \( 1000 \equiv 1 \pmod{37} \)
  • Factors of one thousand and one: \( 1001 = 7\times 11\times 13 \)
  • Repeated three-digit block: \( \overline{abcabc} = \overline{abc}\times 1001 \)
  • Splitting a composite divisor: \( 72 = 8\times 9,\ \gcd(8,9)=1 \)

Revision tips for advanced divisibility problems

  • Split a composite divisor into co-prime factors and apply each rule separately.
  • When the factors are a power of two and nine, settle the last-digits test first and then the digit-sum test; for other factors use their own rules, such as the alternating sum for eleven.
  • For repeated blocks, find how many blocks form a multiple of the divisor and reduce the rest.
  • Group digits in threes from the right with alternating signs to test for seven, eleven and thirteen in one step.

Who should practise this Level 3 set

It suits CAT, IPMAT, SSC and banking aspirants in the final stage of Number System preparation who are already comfortable with the basic divisibility tests.

FAQs about Divisibility Rules Practice Questions with Detailed Solutions – Level 3

What is the divisibility rule of 7?
Double the last digit and subtract it from the number formed by the remaining digits. If the result is divisible by 7, so is the original number, and the step can be repeated for large numbers.
What is the divisibility rule of 11?
Find the difference between the sum of digits in odd places and the sum of digits in even places. The number is divisible by 11 if this difference is zero or a multiple of 11.
What are the divisibility rules from 2 to 11?
A number is divisible by 2, 4 or 8 if its last one, two or three digits form a number divisible by it, by 5 if it ends in 0 or 5, and by 10 if it ends in 0. It is divisible by 3 or 9 if its digit sum is, by 6 if it passes both 2 and 3, while 7 and 11 have their own separate tests.
Why is a number of the form abcabc divisible by 7, 11 and 13?
Such a number equals the three-digit number abc multiplied by 1001. Since 1001 is the product of 7, 11 and 13, every number of this form is divisible by all three.

Test structure

How the paper is split, and how long each part runs. A section you have finished cannot be returned to.

SectionQuestionsTime
Divisibility Rules Level 35075 min

Marking & rules

Total marks
50 across 50 questions.
Negative marking
A wrong answer costs marks. Leaving a question unanswered costs nothing.
Attempts
100 in total. An attempt is spent the moment you begin one.

What you get when you submit

The analysis is ready the moment you submit the paper.

Score and accuracy

Marks, percentage, right, wrong and skipped, and the time you took.

Section by section

The same figures for each section, so a weak one cannot hide in an average.

The full answer key

Every question with your answer, the right one, the working, and the video where there is one.

Where you stand

Your score against the spread of everyone else who has sat this test.

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