RATIO AND PROPORTION Level 2
Q1β10 of 50If $\frac{a}{b}=\frac{b}{c}=\frac{c}{d}$, then $\frac{b^3+c^3+d^3}{a^3+b^3+c^3}$ will be equal to:
If p:q = 3:4, r:s = 8:5Β and x:y = 10:6, then psx:qryΒ is equal to
If \( \dfrac{p}{q} = \dfrac{3}{4} \), \( \dfrac{r}{s} = \dfrac{8}{5} \) and \( \dfrac{x}{y} = \dfrac{10}{6} \), then find \( psx : qry \).
We know that:
\[ \frac{psx}{qry} = \frac{p}{q}\times\frac{s}{r}\times\frac{x}{y} \]
Substituting the values:
\[ = \frac{3}{4}\times\frac{5}{8}\times\frac{10}{6} \]
\[ = \frac{150}{192} = \frac{25}{32} \]
Therefore,
\[ \boxed{25:32} \]
If x/2 = y/3 = z/4 = (2x - 3y + 5z) / k, then
the value of k is:
If \[ \frac{x}{2}=\frac{y}{3}=\frac{z}{4}=\frac{2x-3y+5z}{k} \] then find the value of \( k \).
Let the common value be \( t \).
Then,
\[ x=2t,\quad y=3t,\quad z=4t \]
Substituting in \( 2x-3y+5z \):
\[ =2(2t)-3(3t)+5(4t) \]
\[ =4t-9t+20t \]
\[ =15t \]
Now,
\[ \frac{2x-3y+5z}{k}=t \]
\[ \frac{15t}{k}=t \]
\[ 15t=kt \]
\[ k=15 \]
Therefore,
\[ \boxed{15} \]
ο»ΏIf $a:b=c:d$, then $\frac{ma+nc}{mb+nd}$ is equal to
Let $\frac{a}{b}+\frac{b}{a}=x:y$. If $(x-y)=\left\{\frac{a}{b}+\frac{b}{a}\right\}$, then $x$ is equal to:
If $\frac{a+b}{c}=\frac{b+c}{a}=\frac{c+a}{b}=k$, then $k$ is equal to:
If a : b = 2 : 3 and b : c = 4 : 5, then (a + b) : (b + c) is
equal to:
If a : b = c : d = e : f = 1 : 2, then (3a + 5c + 7e) : (3b +
5d + 7f) is equal to
The fourth proportional to 5, 8, 15 is:
The fourth proportional to 0.12, 0.21 and 8 is: