Profit & Loss Level 2 (1 - 50 Questions)
Q1–10 of 50A shopkeeper sells two watches for ₹308 each.
On one he gets 12% profit and on the other 12% loss.
His profit or loss in the entire transaction was
Step 1: Selling Price (SP)
Both watches are sold at the same selling price.
\( SP_1=308 \) and \( SP_2=308 \).
Total selling price \( =308+308=616 \).
Step 2: Cost Price of the first watch (12% profit)
Profit \( =12\% \).
Formula: \( CP=\dfrac{SP\times100}{100+\text{profit}} \).
\( CP_1=\dfrac{308\times100}{112} \).
\( CP_1=275 \).
Step 3: Cost Price of the second watch (12% loss)
Loss \( =12\% \).
Formula: \( CP=\dfrac{SP\times100}{100-\text{loss}} \).
\( CP_2=\dfrac{308\times100}{88} \).
\( CP_2=350 \).
Step 4: Total Cost Price
\( CP_{\text{total}}=275+350=625 \).
Step 5: Compare total CP and total SP
Total selling price \( =616 \).
Total cost price \( =625 \).
Loss \( =625-616=9 \).
Step 6: Loss percentage
\( \text{Loss\%}=\dfrac{9}{625}\times100 \).
\( \text{Loss\%}=1.44\% \).
Step 7: Convert into mixed fraction
\( 1.44\%=1\dfrac{11}{25}\% \).
Final Answer:
Overall loss
\( =\boxed{1\dfrac{11}{25}\%} \).
A man sells two flats at the rate of ₹1.995 lakhs each.
On one he gains 5% and on the other he loses 5%.
His gain or loss percent in the whole transaction is:
Question
A man sells two flats at the rate of \(1.995\) lakhs each. On one flat he gains \(5\%\) and on the other flat he loses \(5\%\).
Step 1: Selling Price (SP)
Both flats have the same selling price.
\( SP_1 = 1.995 \) lakhs and \( SP_2 = 1.995 \) lakhs.
Total selling price \( = 1.995 + 1.995 = 3.99 \) lakhs.
Step 2: Cost Price of first flat (5% gain)
Formula: \( CP = \dfrac{SP \times 100}{100 + 5} \).
\( CP_1 = \dfrac{1.995 \times 100}{105} \).
\( CP_1 = 1.90 \) lakhs.
Step 3: Cost Price of second flat (5% loss)
Formula: \( CP = \dfrac{SP \times 100}{100 - 5} \).
\( CP_2 = \dfrac{1.995 \times 100}{95} \).
\( CP_2 = 2.10 \) lakhs.
Step 4: Total Cost Price
\( CP_{\text{total}} = 1.90 + 2.10 = 4.00 \) lakhs.
Step 5: Find profit or loss
Total cost price \( = 4.00 \) lakhs.
Total selling price \( = 3.99 \) lakhs.
Loss \( = 4.00 - 3.99 = 0.01 \) lakh.
Step 6: Loss percentage
\( \text{Loss\%} = \ dfrac {0.01}{4.00} \times 100 \).
\( \text{Loss\%} = 0.25\% \).
Final Answer:
Overall loss
\( = \boxed{0.25\%} \).
A man sells two commodities for ₹4000 each, neither losing nor gaining in the deal. If he sold one commodity at a gain of 25%, the other commodity is sold at a loss of:
Question
A man sells two commodities for \(4000\) each, and overall he neither gains nor loses. If one commodity is sold at a gain of \(25\%\), find the loss percent on the other commodity.
Step 1: Selling Price
Both commodities have the same selling price.
\( SP_1 = 4000 \) and \( SP_2 = 4000 \).
Total selling price \( = 4000 + 4000 = 8000 \).
Since there is neither gain nor loss, total cost price \( = 8000 \).
Step 2: Cost Price of first commodity (25% gain)
Formula: \( CP = \dfrac{SP \times 100}{100 + 25} \).
\( CP_1 = \dfrac{4000 \times 100}{125} \).
\( CP_1 = 3200 \).
Step 3: Cost Price of second commodity
Total cost price \( = 8000 \).
\( CP_2 = 8000 - 3200 = 4800 \).
Step 4: Loss on second commodity
Selling price \( = 4000 \).
Cost price \( = 4800 \).
Loss \( = 4800 - 4000 = 800 \).
Step 5: Loss percentage
\( \text{Loss\%} = \dfrac{800}{4800} \times 100 \).
\( \text{Loss\%} = 16\dfrac{2}{3}\% \).
Final Answer:
Loss on the second commodity
\( = \boxed{16\dfrac{2}{3}\%} \).
A house and a shop were sold for ₹1 lakh each.
In this transaction House sale resulted in 20% loss Shop sale resulted in 20% profit The entire transaction resulted in:
Question
A house and a shop were sold for ₹1 lakh each. The house sale resulted in a loss of \(20\%\) and the shop sale resulted in a profit of \(20\%\). Find the overall gain or loss.
Step 1: Selling Price
Selling price of house = \(1\) lakh
Selling price of shop = \(1\) lakh
Total selling price = \(1 + 1 = 2\) lakhs
Step 2: Cost Price of house (20% loss)
\( CP = \dfrac{SP \times 100}{100 - 20} \)
\( CP_{\text{house}} = \dfrac{1 \times 100}{80} = 1.25 \)
Cost price of house = 1.25 lakhs
Step 3: Cost Price of shop (20% profit)
\( CP = \dfrac{SP \times 100}{100 + 20} \)
\( CP_{\text{shop}} = \dfrac{1 \times 100}{120} = 0.8333 \)
Cost price of shop = 0.8333 lakhs
Final Answer
Overall loss = \( \dfrac{1}{12} \) lakh
A man sells two articles at ₹99 each.
He gains 10% on one and loses 10% on the other. Then on overall basis he
Question
A man sells two articles at ₹99 each. He gains \(10\%\) on one article and loses \(10\%\) on the other. Find the overall gain or loss.
Step 1: Selling Price
Selling price of first article = \(99\)
Selling price of second article = \(99\)
Total selling price = \(99 + 99 = 198\)
Step 2: Cost Price of first article (10% gain)
Formula: \( CP = \dfrac{SP \times 100}{100 + 10} \)
\( CP_1 = \dfrac{99 \times 100}{110} = 90 \)
Step 3: Cost Price of second article (10% loss)
Formula: \( CP = \dfrac{SP \times 100}{100 - 10} \)
\( CP_2 = \dfrac{99 \times 100}{90} = 110 \)
Step 4: Total Cost Price
Total cost price \( = 90 + 110 = 200 \)
Step 5: Profit or Loss
Total selling price = \(198\)
Total cost price = \(200\)
Loss \( = 200 - 198 = 2 \)
Final Answer
Overall loss = ₹\(2\)
Correct option: (c)
A man sold two steel chairs for ₹500 each. On one, he gains 20% and on the other he loses 12%. How much does he gain or lose in the whole transaction?
Question
A man sold two steel chairs for ₹500 each. On one chair, he gained \(20\%\) and on the other chair, he lost \(12\%\). Find the overall gain or loss percentage.
Step 1: Selling Price
Selling price of first chair = \(500\)
Selling price of second chair = \(500\)
Total selling price = \(500 + 500 = 1000\)
Step 2: Cost Price of first chair (20% gain)
Formula: \( CP = \dfrac{SP \times 100}{100 + 20} \)
\( CP_1 = \dfrac{500 \times 100}{120} = 416.67 \)
Step 3: Cost Price of second chair (12% loss)
Formula: \( CP = \dfrac{SP \times 100}{100 - 12} \)
\( CP_2 = \dfrac{500 \times 100}{88} = 568.18 \)
Step 4: Total Cost Price
Total cost price \( = 416.67 + 568.18 = 984.85 \)
Step 5: Profit
Total selling price = \(1000\)
Total cost price = \(984.85\)
Profit \( = 1000 - 984.85 = 15.15 \)
Step 6: Profit Percentage
\( \text{Profit\%} = \dfrac{15.15}{984.85} \times 100 \)
\( \text{Profit\%} \approx 1.5\% \)
Final Answer
Overall gain = \( \boxed{1.5\%} \)
Ranjan purchased 120 tables at a price of ₹110 per table. He sold: 30 tables at a profit of ₹12 per table 75 tables at a profit of ₹14 per table Remaining tables at a loss of ₹7 per table What is the average profit per table?
Question
Ranjan purchased \(120\) tables at a price of ₹\(110\) per table. He sold:
- \(30\) tables at a profit of ₹\(12\) per table
- \(75\) tables at a profit of ₹\(14\) per table
- Remaining tables at a loss of ₹\(7\) per table
Find the average profit per table.
Step 1: Total number of tables
Total tables purchased = \(120\)
Tables sold at profit/loss:
Remaining tables \( = 120 - (30 + 75) = 15 \)
Step 2: Calculate total profit
Profit on \(30\) tables \( = 30 \times 12 = 360 \)
Profit on \(75\) tables \( = 75 \times 14 = 1050 \)
Loss on \(15\) tables \( = 15 \times 7 = 105 \)
Step 3: Net profit
Total profit \( = 360 + 1050 = 1410 \)
Net profit \( = 1410 - 105 = 1305 \)
Step 4: Average profit per table
Average profit \( = \dfrac{1305}{120} \)
\( = 10.875 \)
Final Answer
Average profit per table \( = \boxed{₹10.875} \)
Correct option: (b)
Sanket purchased 20 dozen notebooks at ₹48 per dozen. He sold 8 dozen at 10% profit and the remaining 12 dozen with 20% profit. What is his profit percentage in the transaction?
Question
Sanket purchased \(20\) dozen notebooks at ₹\(48\) per dozen. He sold \(8\) dozen at a profit of \(10\%\) and the remaining \(12\) dozen at a profit of \(20\%\). Find his overall profit percentage.
Step 1: Total Cost Price
Cost price per dozen = \(48\)
Total dozens purchased = \(20\)
Total cost price \( = 20 \times 48 = 960 \)
Step 2: Selling price of 8 dozen (10% profit)
Selling price per dozen \( = 48 \times \dfrac{110}{100} = 52.8 \)
Selling price of 8 dozen \( = 8 \times 52.8 = 422.4 \)
Step 3: Selling price of 12 dozen (20% profit)
Selling price per dozen \( = 48 \times \dfrac{120}{100} = 57.6 \)
Selling price of 12 dozen \( = 12 \times 57.6 = 691.2 \)
Step 4: Total Selling Price
Total selling price \( = 422.4 + 691.2 = 1113.6 \)
Step 5: Profit
Profit \( = 1113.6 - 960 = 153.6 \)
Step 6: Profit Percentage
Profit percentage \( = \dfrac{153.6}{960} \times 100 \)
\( = 16\% \)
Final Answer
Overall profit percentage \( = \boxed{16\%} \)
Correct option: (c)
Hemant sold 10 sarees for a total profit of ₹460 and 12 sarees for a total profit of ₹144. At what profit per saree should he sell the remaining 20 sarees so that he gets an average profit of ₹18 per saree?
Question
Hemant sold \(10\) sarees for a total profit of ₹\(460\) and \(12\) sarees for a total profit of ₹\(144\). At what profit per saree should he sell the remaining \(20\) sarees so that he gets an average profit of ₹\(18\) per saree?
Step 1: Total number of sarees
Total sarees \( = 10 + 12 + 20 = 42 \)
Step 2: Total profit required
Average profit per saree = ₹\(18\)
Total profit required \( = 42 \times 18 = 756 \)
Step 3: Profit already earned
Profit on \(10\) sarees = ₹\(460\)
Profit on \(12\) sarees = ₹\(144\)
Total profit earned \( = 460 + 144 = 604 \)
Step 4: Profit required on remaining 20 sarees
Remaining profit \( = 756 - 604 = 152 \)
Step 5: Profit per saree
Profit per saree \( = \dfrac{152}{20} = 7.6 \)
Final Answer
Required profit per saree \( = \boxed{₹7.60} \)
Correct option: (b)
In a shop, 80% of the articles are sold at a profit of 10% and the remaining at a loss of 40%. What is the overall profit/loss?
Question
In a shop, \(80\%\) of the articles are sold at a profit of \(10\%\) and the remaining articles are sold at a loss of \(40\%\). Find the overall profit or loss.
Step 1: Assume total articles
Let total articles = \(100\)
Articles sold at profit = \(80\)
Articles sold at loss = \(20\)
Step 2: Assume cost price
Let cost price per article = \(100\)
Total cost price = \(100 \times 100 = 10000\)
Step 3: Profit on 80 articles (10% profit)
Selling price per article \( = 100 + 10\% \text{ of } 100 = 110 \)
Total selling price of 80 articles \( = 80 \times 110 = 8800 \)
Total cost price of 80 articles \( = 80 \times 100 = 8000 \)
Profit \( = 8800 - 8000 = 800 \)
Step 4: Loss on 20 articles (40% loss)
Selling price per article \( = 100 - 40\% \text{ of } 100 = 60 \)
Total selling price of 20 articles \( = 20 \times 60 = 1200 \)
Total cost price of 20 articles \( = 20 \times 100 = 2000 \)
Loss \( = 2000 - 1200 = 800 \)
Step 5: Overall result
Total profit = \(800\)
Total loss = \(800\)
Net profit/loss \( = 800 - 800 = 0 \)
Final Answer
There is no profit and no loss.
Correct option: (d)