IBPS PO PYQ 2024 QUANTITATIVE APTITUDE
Q1–10 of 35(COMMON INFORMATION FOR THE QUESTIONS 1 - 5)
Read the following data carefully and answer the questions given below. The data shows the three different people (A, B & C) win or lose multiple games. Total games won by B is 50 and the ratio of games won by A and games lost by B is 3:2. The ratio of total games lost by A to total games won by A is 4:3. The number of games lost by A and won by B is 105. Total games won by C is 20% more than total games lost by B and the ratio of total games won to lost by C is 4 : 5.
Q. Total games lost by B is what percentage of the total games won by A?
Ans (a)
Sol. Required percentage = 80/120 × 100 = 66.67%
(COMMON INFORMATION FOR THE QUESTIONS 1 - 5)
Read the following data carefully and answer the questions given below. The data shows the three different people (A, B & C) win or lose multiple games. Total games won by B is 50 and the ratio of games won by A and games lost by B is 3:2. The ratio of total games lost by A to total games won by A is 4:3. The number of games lost by A and won by B is 105. Total games won by C is 20% more than total games lost by B and the ratio of total games won to lost by C is 4 : 5.
Q. Find the sum of games lost by B and A.
Ans (e)
Sol. Required sum = 160 + 80 = 24
(COMMON INFORMATION FOR THE QUESTIONS 1 - 5)
Read the following data carefully and answer the questions given below. The data shows the three different people (A, B & C) win or lose multiple games. Total games won by B is 50 and the ratio of games won by A and games lost by B is 3:2. The ratio of total games lost by A to total games won by A is 4:3. The number of games lost by A and won by B is 105. Total games won by C is 20% more than total games lost by B and the ratio of total games won to lost by C is 4 : 5.
Q. If the total games lost by D are 25% more than that of A and the total games won by D are five more than half of the total games won by C, then find the difference between the total games lost and total games won by D.
Ans (a)
Sol. Total losses of D = 5/4 × 160 = 200
Total wins of D = 96/2 + 5 = 53
Required difference = 200 – 53 = 147
(COMMON INFORMATION FOR THE QUESTIONS 1 - 5)
Read the following data carefully and answer the questions given below. The data shows the three different people (A, B & C) win or lose multiple games. Total games won by B is 50 and the ratio of games won by A and games lost by B is 3:2. The ratio of total games lost by A to total games won by A is 4:3. The number of games lost by A and won by B is 105. Total games won by C is 20% more than total games lost by B and the ratio of total games won to lost by C is 4 : 5.
Q. Find the average of total games won by A & B and total games lost by C.
Ans (d)
Sol. Required average = 120+50+120/3
= 96.67
(COMMON INFORMATION FOR THE QUESTIONS 1 - 5)
Read the following data carefully and answer the questions given below. The data shows the three different people (A, B & C) win or lose multiple games. Total games won by B is 50 and the ratio of games won by A and games lost by B is 3:2. The ratio of total games lost by A to total games won by A is 4:3. The number of games lost by A and won by B is 105. Total games won by C is 20% more than total games lost by B and the ratio of total games won to lost by C is 4 : 5.
Q. Find the average of total games won by A & B and total games lost by C.
Ans (d)
Sol. Required average = 120+50+120/3
= 96.67
(COMMON INFORMATION FOR THE QUESTIONS 6 - 10)
Read the following table carefully and answer the questions given below. The table shows the total number of bikes sold by two (X and Y) different companies in four (K, L, M & N) different cities and the total number of cars sold by these two companies in these cities. The table also shows the total number of bikes sold by company Y in these cities.
| Cities | Bikes sold (X & Y) | Cars sold by (X & Y) | Bikes sold by Y |
| K | 328 | 450 | 210 |
| L | 560 | 980 | 320 |
| M | 440 | 730 | 90 |
| N | 620 | 350 | 195 |
Q. If total number of cars sold by Y in city K are two-fifth of the total number of bikes sold by Y in city K, then find the difference between the total number of cars sold by X in city K and bikes sold by X in city M.
For cities K
Bikes sold by X and Y = 328
Bikes sold by Y = 210
Bikes sold by X = 328-210=118
Similarly,
| Cities | Bikes sold (X & Y) | Cars sold by (X & Y) | Bikes sold by Y |
| K | 118 | 450 | 210 |
| L | 240 | 980 | 320 |
| M | 350 | 730 | 90 |
| N | 425 | 350 | 195 |
Ans (B)
Sol. Total number of cars sold by Y in city K = 2/5× 210 = 84
Total number of cars sold by X in city K = 450 – 84 = 366
Required difference = 366 - 350 = 16
(COMMON INFORMATION FOR THE QUESTIONS 6 - 10)
Read the following table carefully and answer the questions given below. The table shows the total number of bikes sold by two (X and Y) different companies in four (K, L, M & N) different cities and the total number of cars sold by these two companies in these cities. The table also shows the total number of bikes sold by company Y in these cities.
| Cities | Bikes sold (X & Y) | Cars sold by (X & Y) | Bikes sold by Y |
| K | 328 | 450 | 210 |
| L | 560 | 980 | 320 |
| M | 440 | 730 | 90 |
| N | 620 | 350 | 195 |
Q. Total number of cars sold by X in city N is 20% less than the total number of bikes sold by X in city M. Find the ratio of the total number of cars sold by Y in city N to the total number of bikes sold by Y in city K.
For cities K
Bikes sold by X and Y = 328
Bikes sold by Y = 210
Bikes sold by X = 328-210=118
Similarly,
| Cities | Bikes sold (X & Y) | Cars sold by (X & Y) | Bikes sold by Y |
| K | 118 | 450 | 210 |
| L | 240 | 980 | 320 |
| M | 350 | 730 | 90 |
| N | 425 | 350 | 195 |
Ans (e)
Sol. Total number of cars sold by X in city N = 80/100 × 350 =280
Total number of cars sold by Y in city N = 350 – 280 = 70
Required ratio = 70 : 210 = 1:3
(COMMON INFORMATION FOR THE QUESTION 6 - 10)
Read the following table carefully and answer the questions given below. The table shows the total number of bikes sold by two (X and Y) different companies in four (K, L, M & N) different cities and the total number of cars sold by these two companies in these cities. The table also shows the total number of bikes sold by company Y in these cities.
| Cities | Bikes sold (X & Y) | Cars sold by (X & Y) | Bikes sold by Y |
| K | 328 | 450 | 210 |
| L | 560 | 980 | 320 |
| M | 440 | 730 | 90 |
| N | 620 | 350 | 195 |
Q. The ratio of the total number of cars sold by X to Y in city L is 3:4 respectively. Find the total number of cars sold by X in city L is how many more or less than the total number of bikes sold by Y in N.
For cities K
Bikes sold by X and Y = 328
Bikes sold by Y = 210
Bikes sold by X = 328-210=118
Similarly,
| Cities | Bikes sold (X & Y) | Cars sold by (X & Y) | Bikes sold by Y |
| K | 118 | 450 | 210 |
| L | 240 | 980 | 320 |
| M | 350 | 730 | 90 |
| N | 425 | 350 | 195 |
Ans (A)
Sol. Total number of cars sold by X in city L = 980 × 3/7= 420
Required difference = 420 – 195 = 225
(COMMON INFORMATION FOR THE QUESTIONS 6 - 10)
Read the following table carefully and answer the questions given below. The table shows the total number of bikes sold by two (X and Y) different companies in four (K, L, M & N) different cities and the total number of cars sold by these two companies in these cities. The table also shows the total number of bikes sold by company Y in these cities.
| Cities | Bikes sold (X & Y) | Cars sold by (X & Y) | Bikes sold by Y |
| K | 328 | 450 | 210 |
| L | 560 | 980 | 320 |
| M | 440 | 730 | 90 |
| N | 620 | 350 | 195 |
Q. The total number of bikes sold by X in city M is what percentage more or less than the total number of cars sold by X and Y together in city N?
For cities K
Bikes sold by X and Y = 328
Bikes sold by Y = 210
Bikes sold by X = 328-210=118
Similarly,
| Cities | Bikes sold (X & Y) | Cars sold by (X & Y) | Bikes sold by Y |
| K | 118 | 450 | 210 |
| L | 240 | 980 | 320 |
| M | 350 | 730 | 90 |
| N | 425 | 350 | 195 |
Ans (B)
(COMMON INFORMATION FOR THE QUESTIONS 6 - 10)
Read the following table carefully and answer the questions given below. The table shows the total number of bikes sold by two (X and Y) different companies in four (K, L, M & N) different cities and the total number of cars sold by these two companies in these cities. The table also shows the total number of bikes sold by company Y in these cities.
| Cities | Bikes sold (X & Y) | Cars sold by (X & Y) | Bikes sold by Y |
| K | 328 | 450 | 210 |
| L | 560 | 980 | 320 |
| M | 440 | 730 | 90 |
| N | 620 | 350 | 195 |
Q. Total number of cars sold by Y in city M is 200 more than the total number of bikes sold by X in city L. The total number of cars sold by X in city M is what percentage of the total number of cars sold by X and Y together in city K?
For cities K
Bikes sold by X and Y = 328
Bikes sold by Y = 210
Bikes sold by X = 328-210=118
Similarly,
| Cities | Bikes sold (X & Y) | Cars sold by (X & Y) | Bikes sold by Y |
| K | 118 | 450 | 210 |
| L | 240 | 980 | 320 |
| M | 350 | 730 | 90 |
| N | 425 | 350 | 195 |
Ans (A)
Sol. Total number of cars sold by Y in city M = 200 + 240 = 440
Total number of cars sold by X in city M = 730 – 440 = 290
Required percentage = 290/450 × 100 = 64.44% ≈ 64%